4x^2+4x+1=441

Solution for 4x^2+4x+1=441 equation:

Simplifying
4x2 + 4x + 1 = 441

Reorder the terms:
1 + 4x + 4x2 = 441

Solving
1 + 4x + 4x2 = 441

Solving for variable 'x'.

Reorder the terms:
1 + -441 + 4x + 4x2 = 441 + -441

Combine like terms: 1 + -441 = -440
-440 + 4x + 4x2 = 441 + -441

Combine like terms: 441 + -441 = 0
-440 + 4x + 4x2 = 0

Factor out the Greatest Common Factor (GCF), '4'.
4(-110 + x + x2) = 0

Factor a trinomial.
4((-11 + -1x)(10 + -1x)) = 0

Ignore the factor 4.
Subproblem 1
Set the factor '(-11 + -1x)' equal to zero and attempt to solve:

Simplifying
-11 + -1x = 0

Solving
-11 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '11' to each side of the equation.
-11 + 11 + -1x = 0 + 11

Combine like terms: -11 + 11 = 0
0 + -1x = 0 + 11
-1x = 0 + 11

Combine like terms: 0 + 11 = 11
-1x = 11

Divide each side by '-1'.
x = -11

Simplifying
x = -11
Subproblem 2
Set the factor '(10 + -1x)' equal to zero and attempt to solve:

Simplifying
10 + -1x = 0

Solving
10 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + -1x = 0 + -10

Combine like terms: 10 + -10 = 0
0 + -1x = 0 + -10
-1x = 0 + -10

Combine like terms: 0 + -10 = -10
-1x = -10

Divide each side by '-1'.
x = 10

Simplifying
x = 10
Solution
x = {-11, 10}